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In a shop, 2 toy cars cost the same as 1 bag of marbles. Raj bought 12 toy cars and 3 bags of marbles for $72. Find the cost of 1 bag of marbles.A bag of marbles costs $.

Question

In a shop, 2 toy cars cost the same as 1 bag of marbles. Raj bought 12 toy cars and 3 bags of marbles for 72.Findthecostof1bagofmarbles.Abagofmarblescosts72. Find the cost of 1 bag of marbles.A bag of marbles costs .

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Solution

Let's solve this step by step:

Step 1: From the problem, we know that 2 toy cars cost the same as 1 bag of marbles. So, let's denote the cost of 1 bag of marbles as x. Therefore, the cost of 2 toy cars is also x.

Step 2: Raj bought 12 toy cars. Since 2 toy cars cost x, then 12 toy cars cost 6x (because 12 divided by 2 equals 6).

Step 3: Raj also bought 3 bags of marbles, each costing x, so 3 bags of marbles cost 3x.

Step 4: The total cost for 12 toy cars and 3 bags of marbles is 72.So,wecansetuptheequation:6x(thecostforthetoycars)+3x(thecostforthemarbles)=72. So, we can set up the equation: 6x (the cost for the toy cars) + 3x (the cost for the marbles) = 72.

Step 5: Simplify the equation: 9x = $72.

Step 6: Solve for x by dividing both sides of the equation by 9: x = 72/9=72 / 9 = 8.

So, the cost of 1 bag of marbles is $8.

This problem has been solved

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