In a shop, 2 toy cars cost the same as 1 bag of marbles. Raj bought 12 toy cars and 3 bags of marbles for $72. Find the cost of 1 bag of marbles.A bag of marbles costs $.
Question
In a shop, 2 toy cars cost the same as 1 bag of marbles. Raj bought 12 toy cars and 3 bags of marbles for .
Solution
Let's solve this step by step:
Step 1: From the problem, we know that 2 toy cars cost the same as 1 bag of marbles. So, let's denote the cost of 1 bag of marbles as x. Therefore, the cost of 2 toy cars is also x.
Step 2: Raj bought 12 toy cars. Since 2 toy cars cost x, then 12 toy cars cost 6x (because 12 divided by 2 equals 6).
Step 3: Raj also bought 3 bags of marbles, each costing x, so 3 bags of marbles cost 3x.
Step 4: The total cost for 12 toy cars and 3 bags of marbles is 72.
Step 5: Simplify the equation: 9x = $72.
Step 6: Solve for x by dividing both sides of the equation by 9: x = 8.
So, the cost of 1 bag of marbles is $8.
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