Sure, let's solve this step by step:

Step 1: Let's denote the cost of 1 sweet as 's' and the cost of 1 bar of chocolate as 'c'.

Step 2: From the problem, we know that 3 sweets cost the same as 1 bar of chocolate. So, we can write this as an equation: 3s = c.

Step 3: We also know that Michelle bought 6 sweets and 4 bars of chocolate for $162. This can be written as another equation: 6s + 4c = 162.

Step 4: Now we have a system of two equations, and we can solve it. Let's substitute the first equation (3s = c) into the second one: 6s + 4(3s) = 162.

Step 5: Simplify the equation: 6s + 12s = 162.

Step 6: Combine like terms: 18s = 162.

Step 7: Solve for 's': s = 162 / 18 = $9. So, 1 sweet costs $9.

Step 8: Now, let's find the cost of 1 bar of chocolate. Substitute 's' into the first equation: 3s = c, so c = 3 * 9 = $27.

So, 1 bar of chocolate costs $27.

Question

Sure, let's solve this step by step:

Step 1: Let's denote the cost of 1 sweet as 's' and the cost of 1 bar of chocolate as 'c'.

Step 2: From the problem, we know that 3 sweets cost the same as 1 bar of chocolate. So, we can write this as an equation: 3s = c.

Step 3: We also know that Michelle bought 6 sweets and 4 bars of chocolate for $162. This can be written as another equation: 6s + 4c = 162.

Step 4: Now we have a system of two equations, and we can solve it. Let's substitute the first equation (3s = c) into the second one: 6s + 4(3s) = 162.

Step 5: Simplify the equation: 6s + 12s = 162.

Step 6: Combine like terms: 18s = 162.

Step 7: Solve for 's': s = 162 / 18 = $9. So, 1 sweet costs $9.

Step 8: Now, let's find the cost of 1 bar of chocolate. Substitute 's' into the first equation: 3s = c, so c = 3 * 9 = $27.

So, 1 bar of chocolate costs $27.

Knowee AI · Accepted Answer

Sure, let's solve this step by step:

Step 1: Let's denote the cost of 1 sweet as 's' and the cost of 1 bar of chocolate as 'c'.

Step 2: From the problem, we know that 3 sweets cost the same as 1 bar of chocolate. So, we can write this as an equation: 3s = c.

Step 3: We also know that Michelle bought 6 sweets and 4 bars of chocolate for $162. This can be written as another equation: 6s + 4c = 162.

Step 4: Now we have a system of two equations, and we can solve it. Let's substitute the first equation (3s = c) into the second one: 6s + 4(3s) = 162.

Step 5: Simplify the equation: 6s + 12s = 162.

Step 6: Combine like terms: 18s = 162.

Step 7: Solve for 's': s = 162 / 18 = $9. So, 1 sweet costs $9.

Step 8: Now, let's find the cost of 1 bar of chocolate. Substitute 's' into the first equation: 3s = c, so c = 3 * 9 = $27.

So, 1 bar of chocolate costs $27.

In a shop, 3 sweets cost the same as 1 bar of chocolate. Michelle bought 6 sweets and 4 bars of chocolate for $162. Find the cost of 1 bar of chocolate.

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