To solve this problem, we can use the formula for acceleration which is final velocity squared minus initial velocity squared divided by 2 times the distance. In this case, the initial velocity is 0 (since the plane starts from rest), the final velocity is 101 m/s, and the distance is 1230 m.

So, the acceleration (a) can be calculated as follows:

a = (Vf^2 - Vi^2) / (2*d)

where:
Vf = final velocity = 101 m/s,
Vi = initial velocity = 0 m/s (since the plane is initially at rest),
d = distance = 1230 m.

Substituting the values into the formula, we get:

a = (101^2 - 0^2) / (2*1230)
a = (10201 - 0) / 2460
a = 10201 / 2460
a = 4.15 m/s^2

So, the required acceleration of the plane to reach the takeoff speed is approximately 4.15 m/s^2.

Question

To solve this problem, we can use the formula for acceleration which is final velocity squared minus initial velocity squared divided by 2 times the distance. In this case, the initial velocity is 0 (since the plane starts from rest), the final velocity is 101 m/s, and the distance is 1230 m.

So, the acceleration (a) can be calculated as follows:

a = (Vf^2 - Vi^2) / (2*d)

where:
Vf = final velocity = 101 m/s,
Vi = initial velocity = 0 m/s (since the plane is initially at rest),
d = distance = 1230 m.

Substituting the values into the formula, we get:

a = (101^2 - 0^2) / (2*1230)
a = (10201 - 0) / 2460
a = 10201 / 2460
a = 4.15 m/s^2

So, the required acceleration of the plane to reach the takeoff speed is approximately 4.15 m/s^2.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for acceleration which is final velocity squared minus initial velocity squared divided by 2 times the distance. In this case, the initial velocity is 0 (since the plane starts from rest), the final velocity is 101 m/s, and the distance is 1230 m.

So, the acceleration (a) can be calculated as follows:

a = (Vf^2 - Vi^2) / (2*d)

where:
Vf = final velocity = 101 m/s,
Vi = initial velocity = 0 m/s (since the plane is initially at rest),
d = distance = 1230 m.

Substituting the values into the formula, we get:

a = (101^2 - 0^2) / (2*1230)
a = (10201 - 0) / 2460
a = 10201 / 2460
a = 4.15 m/s^2

So, the required acceleration of the plane to reach the takeoff speed is approximately 4.15 m/s^2.

Skrr, skrr, zoom, zoom. A plane requires a ground run of 1230 [m] to reach a takeoff speed of 101 [m/s]. What is the required acceleration of the plane to reach this takeoff speed.

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