Find out the Simplified Boolean function using Karnaugh map method for the function F (A, B, C, D) = Σm (1, 5, 9, 12, 13, 15) is *F= ABD+ C’D+ ABCF= ABD+ C’D+ AB’C’F= AB’D+ C’D+ AB’C’F= ABD’+ C’D+ AB’C’

The given function is F (A, B, C, D) = Σm (1, 5, 9, 12, 13, 15). We will use the Karnaugh map method to simplify this function.

Step 1: Draw a 4-variable Karnaugh map. The variables A and B will represent the rows and the variables C and D will represent the columns.

Step 2: Plot the given min terms (1, 5, 9, 12, 13, 15) on the Karnaugh map.

Step 3: Group the adjacent 1s in the Karnaugh map. The groups should be made in such a way that the size of the group is a power of 2 (1, 2, 4, 8, etc.) and the group must be as large as possible. Also, the groups can overlap.

Step 4: Write the simplified Boolean expression for each group.

• For the group covering the min terms 1 and 5, the simplified expression is C'D.
• For the group covering the min terms 9, 13 and 15, the simplified expression is ABD.
• For the group covering the min terms 12, 13 and 15, the simplified expression is ABC.

Step 5: Combine all the simplified expressions using the OR operation to get the final simplified function.

So, the simplified Boolean function is F = ABD + C'D + ABC.

Please note that the expressions you provided in the question seem to be incorrect as they do not match with the simplified function obtained from the Karnaugh map method.