What will be the output of the following C code?#include  <stdio.h>    int main()    {       signed char chr;       chr = 128;       printf("%d\n", chr);       return 0;    }a.-128b.128c.Depends on the compilerd.Compiler Error

The output of the given C code will be -128.

Here's why:

In C, the range of values that can be represented by a signed char is from -128 to 127. When you try to assign a value of 128 to a signed char, it overflows and wraps around to the beginning of the range, which is -128. So, the output of the code will be -128.

Therefore, the correct answer is a. -128.