15 years ago, a father was three times as old as his daughter.Now the father is only twice as old as his daughter.Find the sum of the present ages of daughter and father.546590108
Question
15 years ago, a father was three times as old as his daughter.Now the father is only twice as old as his daughter.Find the sum of the present ages of daughter and father.546590108
Solution
Let's denote the present age of the daughter as D and the present age of the father as F.
From the problem, we know that:
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15 years ago, the father was three times as old as his daughter. This can be written as: F - 15 = 3 * (D - 15)
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Now, the father is twice as old as his daughter. This can be written as: F = 2 * D
We can solve these two equations to find the values of D and F.
First, let's substitute the second equation into the first:
2D - 15 = 3D - 45
This simplifies to:
D = 30
Substitute D = 30 into the second equation:
F = 2 * 30 = 60
So, the daughter is 30 years old and the father is 60 years old.
The sum of their ages is:
D + F = 30 + 60 = 90 years.
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