Five years ago, the age of a mother was four times the age of her daughter.Fifteen years hence, the mother’s age will be twice the age the daughter.Find the present age of the daughter,
Question
Five years ago, the age of a mother was four times the age of her daughter.Fifteen years hence, the mother’s age will be twice the age the daughter.Find the present age of the daughter,
Solution
Let's denote the present age of the daughter as x and the present age of the mother as y.
From the problem, we have two equations:
-
Five years ago, the mother was four times older than her daughter. This can be written as: y - 5 = 4 * (x - 5).
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In fifteen years, the mother will be twice as old as her daughter. This can be written as: y + 15 = 2 * (x + 15).
Now we can solve these two equations.
First, simplify them:
- y - 4x = -15
- y - 2x = 15
Subtract the second equation from the first to eliminate y:
-4x + 2x = -15 - 15 -2x = -30 x = 15
Substitute x = 15 into the second equation:
y - 2*15 = 15 y = 45
So, the present age of the daughter is 15 years old and the present age of the mother is 45 years old.
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