This problem can be solved using the principle of conservation of momentum. The total momentum before the push is zero (since they are stationary), and the total momentum after the push should also be zero (since no external force is acting on the system).

The momentum of the first skater after the push is his mass times his velocity, which is 64.1 kg * 1 m/s = 64.1 kg*m/s.

The momentum of the second skater after the push is his mass times his velocity. We don't know his mass (let's call it m), but we know his velocity is 1.6 m/s. So his momentum is m * 1.6 m/s.

Since the total momentum must be zero, the momentum of the first skater must be equal and opposite to the momentum of the second skater. So we can set up the equation:

64.1 kg*m/s = m * 1.6 m/s

Solving for m gives us:

m = 64.1 kg*m/s / 1.6 m/s = 40.0625 kg

So the mass of the second skater is approximately 40.1 kg.

Question

This problem can be solved using the principle of conservation of momentum. The total momentum before the push is zero (since they are stationary), and the total momentum after the push should also be zero (since no external force is acting on the system).

The momentum of the first skater after the push is his mass times his velocity, which is 64.1 kg * 1 m/s = 64.1 kg*m/s.

The momentum of the second skater after the push is his mass times his velocity. We don't know his mass (let's call it m), but we know his velocity is 1.6 m/s. So his momentum is m * 1.6 m/s.

Since the total momentum must be zero, the momentum of the first skater must be equal and opposite to the momentum of the second skater. So we can set up the equation:

64.1 kg*m/s = m * 1.6 m/s

Solving for m gives us:

m = 64.1 kg*m/s / 1.6 m/s = 40.0625 kg

So the mass of the second skater is approximately 40.1 kg.

Knowee AI · Accepted Answer

This problem can be solved using the principle of conservation of momentum. The total momentum before the push is zero (since they are stationary), and the total momentum after the push should also be zero (since no external force is acting on the system).

The momentum of the first skater after the push is his mass times his velocity, which is 64.1 kg * 1 m/s = 64.1 kg*m/s.

The momentum of the second skater after the push is his mass times his velocity. We don't know his mass (let's call it m), but we know his velocity is 1.6 m/s. So his momentum is m * 1.6 m/s.

Since the total momentum must be zero, the momentum of the first skater must be equal and opposite to the momentum of the second skater. So we can set up the equation:

64.1 kg*m/s = m * 1.6 m/s

Solving for m gives us:

m = 64.1 kg*m/s / 1.6 m/s = 40.0625 kg

So the mass of the second skater is approximately 40.1 kg.

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