Two students are sliding a 34.3 kg mass upa 36.2 degrees ramp. Both are exerting their forces parallel to the surface. One student is at the top of the ramp, pulling the mass up it via a rope with a force of 254 N. The other students is pushing the mass up the ramp, using a force of 176 N. The cofficient of kinetic friction is 0.431. Determine the acceleration of the mass.
Question
Two students are sliding a 34.3 kg mass upa 36.2 degrees ramp. Both are exerting their forces parallel to the surface. One student is at the top of the ramp, pulling the mass up it via a rope with a force of 254 N. The other students is pushing the mass up the ramp, using a force of 176 N. The cofficient of kinetic friction is 0.431. Determine the acceleration of the mass.
Solution
Sure, let's solve this step by step:
Step 1: Identify the forces acting on the mass
- The force of gravity (Fg) acting downwards
- The normal force (Fn) acting perpendicular to the ramp
- The force of friction (Ff) acting opposite to the direction of motion
- The force exerted by the students (Fp) acting up the ramp
Step 2: Calculate the force of gravity (Fg) Fg = m * g Fg = 34.3 kg * 9.8 m/s^2 Fg = 335.74 N
Step 3: Calculate the component of gravity acting along the ramp (Fg_parallel) Fg_parallel = Fg * sin(θ) Fg_parallel = 335.74 N * sin(36.2 degrees) Fg_parallel = 199.99 N
Step 4: Calculate the normal force (Fn) Fn = Fg * cos(θ) Fn = 335.74 N * cos(36.2 degrees) Fn = 270.68 N
Step 5: Calculate the force of friction (Ff) Ff = μ * Fn Ff = 0.431 * 270.68 N Ff = 116.64 N
Step 6: Calculate the total force exerted by the students (Fp) Fp = 254 N (force by the student pulling) + 176 N (force by the student pushing) Fp = 430 N
Step 7: Calculate the net force acting on the mass (Fnet) Fnet = Fp - Fg_parallel - Ff Fnet = 430 N - 199.99 N - 116.64 N Fnet = 113.37 N
Step 8: Calculate the acceleration of the mass (a) a = Fnet / m a = 113.37 N / 34.3 kg a = 3.3 m/s^2
So, the acceleration of the mass is 3.3 m/s^2.
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