The average of four consecutive odd numbers is given as 108.

Step 1: The average of a set of numbers is the sum of the numbers divided by the count of numbers. In this case, the sum of the four consecutive odd numbers is 108 * 4 = 432.

Step 2: Consecutive odd numbers increase by 2. So, if we consider the four numbers to be (n-3), (n-1), (n+1), (n+3), their sum would be 4n = 432.

Step 3: Solving for n, we get n = 432 / 4 = 108.

Step 4: The third number in ascending order would be (n+1) = 108 + 1 = 109.

So, the third number in ascending order is 109.

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The average of four consecutive odd numbers is given as 108.

Step 1: The average of a set of numbers is the sum of the numbers divided by the count of numbers. In this case, the sum of the four consecutive odd numbers is 108 * 4 = 432.

Step 2: Consecutive odd numbers increase by 2. So, if we consider the four numbers to be (n-3), (n-1), (n+1), (n+3), their sum would be 4n = 432.

Step 3: Solving for n, we get n = 432 / 4 = 108.

Step 4: The third number in ascending order would be (n+1) = 108 + 1 = 109.

So, the third number in ascending order is 109.

Knowee AI · Accepted Answer

The average of four consecutive odd numbers is given as 108.

Step 1: The average of a set of numbers is the sum of the numbers divided by the count of numbers. In this case, the sum of the four consecutive odd numbers is 108 * 4 = 432.

Step 2: Consecutive odd numbers increase by 2. So, if we consider the four numbers to be (n-3), (n-1), (n+1), (n+3), their sum would be 4n = 432.

Step 3: Solving for n, we get n = 432 / 4 = 108.

Step 4: The third number in ascending order would be (n+1) = 108 + 1 = 109.

So, the third number in ascending order is 109.

Average of four consecutive odd numbers is 108. What is the third number in ascending order? Options107109111cannot be determined

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