If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?202422None of these
Question
If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?202422None of these
Solution
Let's solve this step by step:
Step 1: Let's assume the three consecutive even numbers are x, x+2, and x+4.
Step 2: The sum of these numbers is x + (x+2) + (x+4) = 3x + 6.
Step 3: The average of these numbers is (x + (x+2) + (x+4))/3 = x + 2.
Step 4: According to the problem, the sum of the numbers is 44 more than their average. So, we can set up the following equation: 3x + 6 = x + 2 + 44.
Step 5: Simplify the equation to get 2x = 40.
Step 6: Solve for x to get x = 20.
Step 7: The largest of these numbers is x + 4 = 20 + 4 = 24.
So, the largest of these numbers is 24.
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