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A vector has a horizontal component of 25m pointing right, and a vertical component of 30m pointing upwards. What is the direction of this vector, to the nearest degree?

Question

A vector has a horizontal component of 25m pointing right, and a vertical component of 30m pointing upwards. What is the direction of this vector, to the nearest degree?

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Solution

To find the direction of the vector, we can use the tangent function in trigonometry. The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side.

Here, the vertical component of the vector can be considered as the opposite side, and the horizontal component as the adjacent side.

So, the angle θ (in degrees) can be found using the formula:

θ = tan^-1(opposite/adjacent)

Substituting the given values:

θ = tan^-1(30/25)

Use a calculator to find the inverse tangent of (30/25), and round to the nearest degree.

This will give you the direction of the vector.

This problem has been solved

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