Here is a step-by-step solution in Python:

1. First, convert the input number into a string to easily access each digit:

```python
num = str(input())
```

2. Initialize a variable to store the sum of the differences:

```python
sum_diff = 0
```

3. Use a loop to iterate over the digits from both ends towards the middle. The range of the loop is half the length of the number string. If the length of the number string is odd, the middle digit will be included in the loop:

```python
for i in range(len(num)//2):
```

4. In each iteration, calculate the absolute difference between the digit at the current index from the left (i) and the digit at the corresponding index from the right (-i-1). Add this difference to the sum:

```python
sum_diff += abs(int(num[i]) - int(num[-i-1]))
```

5. If the length of the number string is odd, add the middle digit to the sum:

```python
if len(num) % 2 != 0:
sum_diff += int(num[len(num)//2])
```

6. Finally, print the sum of the differences:

```python
print(sum_diff)
```

Here is the complete code:

```python
num = str(input())
sum_diff = 0
for i in range(len(num)//2):
sum_diff += abs(int(num[i]) - int(num[-i-1]))
if len(num) % 2 != 0:
sum_diff += int(num[len(num)//2])
print(sum_diff)
```

Question

Here is a step-by-step solution in Python:

1. First, convert the input number into a string to easily access each digit:

```python
num = str(input())
```

2. Initialize a variable to store the sum of the differences:

```python
sum_diff = 0
```

3. Use a loop to iterate over the digits from both ends towards the middle. The range of the loop is half the length of the number string. If the length of the number string is odd, the middle digit will be included in the loop:

```python
for i in range(len(num)//2):
```

4. In each iteration, calculate the absolute difference between the digit at the current index from the left (i) and the digit at the corresponding index from the right (-i-1). Add this difference to the sum:

```python
    sum_diff += abs(int(num[i]) - int(num[-i-1]))
```

5. If the length of the number string is odd, add the middle digit to the sum:

```python
if len(num) % 2 != 0:
    sum_diff += int(num[len(num)//2])
```

6. Finally, print the sum of the differences:

```python
print(sum_diff)
```

Here is the complete code:

```python
num = str(input())
sum_diff = 0
for i in range(len(num)//2):
    sum_diff += abs(int(num[i]) - int(num[-i-1]))
if len(num) % 2 != 0:
    sum_diff += int(num[len(num)//2])
print(sum_diff)
```

Knowee AI · Accepted Answer