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Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40minutes to arrive at school. Bill arrives 20 minutes after Amy. How much faster (in meters/second) is Amy’s averagespeed for the entire trip

Question

Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40minutes to arrive at school. Bill arrives 20 minutes after Amy. How much faster (in meters/second) is Amy’s averagespeed for the entire trip

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Solution

Primero, vamos a convertir la distancia de kilómetros a metros. Sabemos que 1 kilómetro equivale a 1000 metros.

14.4 kilómetros * 1000 = 14400 metros

Ahora, convertimos el tiempo de Amy de minutos a segundos. Sabemos que 1 minuto equivale a 60 segundos.

40 minutos * 60 = 2400 segundos

La velocidad promedio de Amy se calcula dividiendo la distancia total por el tiempo total.

Velocidad de Amy = 14400 metros / 2400 segundos = 6 metros/segundo

Bill llega 20 minutos después de Amy, así que su tiempo total de viaje es:

40 minutos + 20 minutos = 60 minutos

Convertimos el tiempo de Bill a segundos:

60 minutos * 60 = 3600 segundos

La velocidad promedio de Bill se calcula de la misma manera:

Velocidad de Bill = 14400 metros / 3600 segundos = 4 metros/segundo

Finalmente, para encontrar cuán más rápida es la velocidad promedio de Amy en comparación con la de Bill, restamos la velocidad de Bill de la velocidad de Amy:

Diferencia de velocidad = 6 metros/segundo - 4 metros/segundo = 2 metros/segundo

Por lo tanto, Amy es 2 metros/segundo más rápida que Bill.

This problem has been solved

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