The work done by a force F = 4 ax – 3 ay + 2 az N in giving a 1 nC charge a displacement of 10 ax + 2 ay - 7 az m isans.20 n Joule40 n Joule 60 n Joule 103 n Joule Previous Marked for Review Next
Question
The work done by a force F = 4 ax – 3 ay + 2 az N in giving a 1 nC charge a displacement of 10 ax + 2 ay - 7 az m isans.20 n Joule40 n Joule 60 n Joule 103 n Joule Previous Marked for Review Next
Solution
The work done by a force is given by the dot product of the force vector and the displacement vector.
The force vector F is given as F = 4 ax – 3 ay + 2 az N. The displacement vector d is given as d = 10 ax + 2 ay - 7 az m.
The dot product of two vectors is calculated as follows:
F . d = Fx * dx + Fy * dy + Fz * dz
Substituting the given values into the formula, we get:
F . d = (4 N * 10 m) + (-3 N * 2 m) + (2 N * -7 m) = 40 Nm - 6 Nm - 14 Nm = 20 Nm
Therefore, the work done by the force is 20 n Joule.
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