A point charge of 5 C is moved from a point of –10 V to a point of V0 volt and the work done by external force in the process is 100 J, the value of V0 is
Question
A point charge of 5 C is moved from a point of –10 V to a point of V0 volt and the work done by external force in the process is 100 J, the value of V0 is
Solution
The work done by an external force in moving a charge from one point to another is given by the equation:
W = q * (Vf - Vi)
where: W is the work done, q is the charge, Vf is the final potential, and Vi is the initial potential.
In this case, we know that: W = 100 J, q = 5 C, Vi = -10 V, and Vf = V0 (which we're trying to find).
Substituting these values into the equation gives us:
100 J = 5 C * (V0 - (-10 V))
Solving for V0, we get:
V0 = 100 J / 5 C + 10 V V0 = 20 V + 10 V V0 = 30 V
So, the final potential (V0) is 30 volts.
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