Use the exact values you enter to make later calculations.A group of students performed the same "Conservation of Mechanical Energy" experiment that you performed in lab. However, instead of keeping the horizontal portion of the ramp at a constant height h2 from the tabletop, they varied this height and released the ball from the same height h1 each time. They then entered their results into the first two columns of the table shown in part (a).(a) Complete the table below.Trial # Height of ramp from table top h2 (cm) Horizontal distance d (cm) v2kin (cm/s)1 11.23 30.24 2 22.93 40.92 3 31.86 47.87 4 43.20 54.42 5 49.70 58.30 (b) Use the average value of v2kin to determine the height h1 through which the ball falls.

A ball is rolled horizontally off a table with an initial speed of 0.21 m/s. A stopwatch measures the ball's trajectory time from table to the floor to be 0.3 s. What is the height of the table? (g = 9.8 m/s2 and air resistance is negligible)​Select one:a.0.44 mb.​0.45 mc.0.01 md.0.38 me.0.5 m

The mass of the ball bearing in the Conservation of Energy experiment is doubled.  How does the final horizontal displacement of the ball from the release point, D, change?

A 6.7 kg bowling ball is lifted 1.8 m into a storage rack. Calculate the increase in the ball's potential energy.

Select trial 15. Your answers will be based on measurements made from trial 15.Consider the procedure you wrote above. In order to find the height reached by the puck, you will need to find the speed of the puck after it has been pushed but before it begins to slide up the curved ramp.What velocity did you measure/calculate for the puck after it has been pushed but before it begins to slide up the curved ramp?

A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 2m. If the cricket player wants to release the ball such that its velocity is exactly parallel to the ground, and the velocity is actually 40 ms-1. Calculate the total mechanical energy of the cricket ball as it is released? Give your answer to zero decimal places in units of J. Do not include the units in your answer i.e. you would write 13 J as 13