A ball is rolled horizontally off a table with an initial speed of 0.21 m/s. A stopwatch measures the ball's trajectory time from table to the floor to be 0.3 s. What is the height of the table? (g = 9.8 m/s2 and air resistance is negligible)Select one:a.0.44 mb.0.45 mc.0.01 md.0.38 me.0.5 m
Question
A ball is rolled horizontally off a table with an initial speed of 0.21 m/s. A stopwatch measures the ball's trajectory time from table to the floor to be 0.3 s. What is the height of the table? (g = 9.8 m/s2 and air resistance is negligible)Select one:a.0.44 mb.0.45 mc.0.01 md.0.38 me.0.5 m
Solution
To solve this problem, we need to use the equation of motion that describes the vertical displacement of an object under constant acceleration. This equation is:
h = 0.5 * g * t^2
where:
- h is the height of the table,
- g is the acceleration due to gravity, and
- t is the time it takes for the ball to hit the floor.
Given that g = 9.8 m/s^2 and t = 0.3 s, we can substitute these values into the equation to find h:
h = 0.5 * 9.8 m/s^2 * (0.3 s)^2 h = 0.5 * 9.8 m/s^2 * 0.09 s^2 h = 0.441 m
So, the height of the table is approximately 0.44 m. Therefore, the correct answer is a. 0.44 m.
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