To solve this problem, we can use the combined gas law which states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state. The formula is (P1*V1)/T1 = (P2*V2)/T2.

First, we need to convert the temperatures from Celsius to Kelvin because the gas laws require the use of absolute temperatures. We can do this by adding 273.15 to the Celsius temperature.

T1 = 37.0°C + 273.15 = 310.15 K
T2 = 65.0°C + 273.15 = 338.15 K

Now we can substitute the given values into the combined gas law formula and solve for P2.

(P1*V1)/T1 = (P2*V2)/T2
(0.950 atm * 1.75 L) / 310.15 K = (P2 * 1.18 L) / 338.15 K

Solving for P2 gives us:

P2 = (0.950 atm * 1.75 L * 338.15 K) / (310.15 K * 1.18 L) = 1.54 atm

So, the pressure that the SF6 will exert is 1.54 atm.

Question

To solve this problem, we can use the combined gas law which states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state. The formula is (P1*V1)/T1 = (P2*V2)/T2.

First, we need to convert the temperatures from Celsius to Kelvin because the gas laws require the use of absolute temperatures. We can do this by adding 273.15 to the Celsius temperature.

T1 = 37.0°C + 273.15 = 310.15 K
T2 = 65.0°C + 273.15 = 338.15 K

Now we can substitute the given values into the combined gas law formula and solve for P2.

(P1*V1)/T1 = (P2*V2)/T2
(0.950 atm * 1.75 L) / 310.15 K = (P2 * 1.18 L) / 338.15 K

Solving for P2 gives us:

P2 = (0.950 atm * 1.75 L * 338.15 K) / (310.15 K * 1.18 L) = 1.54 atm

So, the pressure that the SF6 will exert is 1.54 atm.

Knowee AI · Accepted Answer

To solve this problem, we can use the combined gas law which states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state. The formula is (P1*V1)/T1 = (P2*V2)/T2.

First, we need to convert the temperatures from Celsius to Kelvin because the gas laws require the use of absolute temperatures. We can do this by adding 273.15 to the Celsius temperature.

T1 = 37.0°C + 273.15 = 310.15 K
T2 = 65.0°C + 273.15 = 338.15 K

Now we can substitute the given values into the combined gas law formula and solve for P2.

(P1*V1)/T1 = (P2*V2)/T2
(0.950 atm * 1.75 L) / 310.15 K = (P2 * 1.18 L) / 338.15 K

Solving for P2 gives us:

P2 = (0.950 atm * 1.75 L * 338.15 K) / (310.15 K * 1.18 L) = 1.54 atm

So, the pressure that the SF6 will exert is 1.54 atm.

A sample of SF6 gas in an expandable container occupies 1.75 L at 0.950 atm and 37.0°C. If the temperature is increased to 65.0°C and the volume decreases to 1.18 L, what pressure will the SF6 exert?Multiple choice question.2.48 atm0.588 atm1.29 atm1.54 atm

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