for (int i = 0; i < arr.length-1; i++){ for (int j = i+1; j < arr.length; j++) { if( (arr[i].equals(arr[j])) && (i != j) ) { System.out.println(arr[i]); } }}
Question
for (int i = 0; i < arr.length-1; i++){ for (int j = i+1; j < arr.length; j++) { if( (arr[i].equals(arr[j])) && (i != j) ) { System.out.println(arr[i]); } }}
Solution
This is a piece of code written in Java. It's a nested loop that checks for duplicate elements in an array. Here's a step-by-step explanation:
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The outer loop starts with the first element of the array (at index 0).
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The inner loop starts with the element next to the current element of the outer loop (at index i+1).
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The 'if' condition checks if the current element of the outer loop is equal to the current element of the inner loop, and also ensures that the indices of the two elements are not the same (to avoid comparing an element with itself).
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If the condition is true, it means a duplicate element is found. The duplicate element is then printed out.
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The inner loop continues for the rest of the elements in the array.
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Once the inner loop is finished, the outer loop moves to the next element and the process is repeated.
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This continues until all elements in the array have been compared.
Similar Questions
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What does the following piece of code do?for (int i = 0; i < arr.length-1; i++){ for (int j = i+1; j < arr.length; j++) { if( (arr[i].equals(arr[j])) && (i != j) ) { System.out.println(arr[i]); } }}
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