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Suppose that 6 J of work is needed to stretch a spring from its natural length of 32 cm to a length of 50 cm.(a)How much work (in J) is needed to stretch the spring from 37 cm to 45 cm? (Round your answer to two decimal places.)

Question

Suppose that 6 J of work is needed to stretch a spring from its natural length of 32 cm to a length of 50 cm.(a)How much work (in J) is needed to stretch the spring from 37 cm to 45 cm? (Round your answer to two decimal places.)

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Solution

To solve this problem, we need to use Hooke's Law, which states that the force needed to extend or compress a spring by some distance is proportional to that distance. That is:

F = kx

where: F is the force applied, k is the spring constant, and x is the distance the spring is stretched or compressed.

Work is defined as the force applied over a distance, so the work done on the spring can be calculated as:

W = 1/2 kx^2

Given that 6J of work is needed to stretch the spring from its natural length of 32 cm to a length of 50 cm, we can set up the equation:

6 = 1/2 k (50-32)^2

Solving for k, we get:

k = 2*6 / (50-32)^2 = 0.027 J/cm^2

Now, we can calculate the work needed to stretch the spring from 37 cm to 45 cm:

W = 1/2 * 0.027 * (45-37)^2 = 0.216 J

So, approximately 0.22 J of work is needed to stretch the spring from 37 cm to 45 cm.

This problem has been solved

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