How much work must be done to compress a spring a distance of 36.0 cm from its equilibrium position if thespring has an elastic constant of 3.25 x 10 3N/m?a. 1.17 x 103 c. 4.21 x 102Jb. 5.85 x 102J d. 2.11 x102J
Question
How much work must be done to compress a spring a distance of 36.0 cm from its equilibrium position if thespring has an elastic constant of 3.25 x 10 3N/m?a. 1.17 x 103 c. 4.21 x 102Jb. 5.85 x 102J d. 2.11 x102J
Solution
The work done on a spring is given by the formula W = 1/2 * k * x^2, where:
- W is the work done,
- k is the spring constant, and
- x is the distance the spring is stretched or compressed from its equilibrium position.
Given in the problem, k = 3.25 x 10^3 N/m and x = 36.0 cm = 0.36 m (since 1 m = 100 cm).
Substituting these values into the formula, we get:
W = 1/2 * (3.25 x 10^3 N/m) * (0.36 m)^2 W = 0.5 * 3.25 x 10^3 N/m * 0.1296 m^2 W = 210.6 Joules
So, the closest answer is d. 2.11 x 10^2 J.
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