A 20 N metal block suspended by a spring balance. A beaker containing some water is placed on a weighing machine which reads 32 N. The spring balance is now lowered so that the block gets immersed in the water. The spring balance now reads 16 N. The reading of the weighing machine will be
Question
A 20 N metal block suspended by a spring balance. A beaker containing some water is placed on a weighing machine which reads 32 N. The spring balance is now lowered so that the block gets immersed in the water. The spring balance now reads 16 N. The reading of the weighing machine will be
Solution
The weight of the metal block in air is 20 N and when it is immersed in water, the weight is reduced to 16 N. This means that the buoyant force exerted by the water on the block is 20 N - 16 N = 4 N.
The buoyant force is equal to the weight of the water displaced by the block. So, when the block is immersed in the water, the weight of the water in the beaker increases by the weight of the water displaced by the block, which is 4 N.
Therefore, the new reading of the weighing machine will be the original weight of the beaker and the water (32 N) plus the weight of the water displaced by the block (4 N), which is 32 N + 4 N = 36 N.
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