A boy whose mass is 50kg stands on a spring balance inside a lift. The lift starts to ascent with an acceleration of 2ms−2.2𝑚𝑠−2. The reading of the machine or balance is (g=10 ms−2)(𝑔=10 ms−2)
Question
A boy whose mass is 50kg stands on a spring balance inside a lift. The lift starts to ascent with an acceleration of 2ms−2.2𝑚𝑠−2. The reading of the machine or balance is (g=10 ms−2)(𝑔=10 ms−2)
Solution
The force acting on the boy is the sum of the gravitational force and the force due to the acceleration of the lift.
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First, calculate the gravitational force acting on the boy. This is given by the equation F = m*g, where m is the mass of the boy and g is the acceleration due to gravity.
F_gravity = 50kg * 10ms^-2 = 500N
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Next, calculate the force due to the acceleration of the lift. This is given by the equation F = m*a, where m is the mass of the boy and a is the acceleration of the lift.
F_lift = 50kg * 2ms^-2 = 100N
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Add these two forces together to find the total force acting on the boy.
F_total = F_gravity + F_lift = 500N + 100N = 600N
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The reading on the spring balance is equal to the total force acting on the boy divided by the acceleration due to gravity.
Reading = F_total / g = 600N / 10ms^-2 = 60kg
So, the reading on the spring balance would be 60kg.
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