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Evaluate ๐‘™๐‘–๐‘š๐œƒโ†’0 [๐‘ ๐‘–๐‘›๐œƒโˆ’๐‘ก๐‘Ž๐‘›๐œƒ๐‘ ๐‘–๐‘›3 ๐œƒ ]

Question

Evaluate ๐‘™๐‘–๐‘š๐œƒโ†’0 [๐‘ ๐‘–๐‘›๐œƒโˆ’๐‘ก๐‘Ž๐‘›๐œƒ๐‘ ๐‘–๐‘›3 ๐œƒ ]

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Solution

To evaluate the limit as ๐œƒ approaches 0 of [๐‘ ๐‘–๐‘›๐œƒโˆ’๐‘ก๐‘Ž๐‘›๐œƒ๐‘ ๐‘–๐‘›3 ๐œƒ], we can use the properties of limits and trigonometric identities.

Step 1: Simplify the expression inside the limit: ๐‘ ๐‘–๐‘›๐œƒโˆ’๐‘ก๐‘Ž๐‘›๐œƒ๐‘ ๐‘–๐‘›3 ๐œƒ = ๐‘ ๐‘–๐‘›๐œƒ โˆ’ ๐‘ ๐‘–๐‘›3 ๐œƒ/๐‘๐‘œ๐‘ ๐œƒ

Step 2: Apply the trigonometric identity sin(๐‘Ž) โˆ’ sin(๐‘) = 2sin((๐‘Žโˆ’๐‘)/2)cos((๐‘Ž+๐‘)/2) to simplify further: ๐‘ ๐‘–๐‘›๐œƒ โˆ’ ๐‘ ๐‘–๐‘›3 ๐œƒ/๐‘๐‘œ๐‘ ๐œƒ = 2sin((๐œƒโˆ’3๐œƒ)/2)cos((๐œƒ+3๐œƒ)/2)/๐‘๐‘œ๐‘ ๐œƒ

Simplifying the angles: 2sin((-2๐œƒ)/2)cos((4๐œƒ)/2)/๐‘๐‘œ๐‘ ๐œƒ = 2sin(-๐œƒ)cos(2๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ

Step 3: Apply the trigonometric identity sin(-๐‘Ž) = -sin(๐‘Ž) to simplify further: 2sin(-๐œƒ)cos(2๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ = -2sin(๐œƒ)cos(2๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ

Step 4: Apply the trigonometric identity cos(2๐‘Ž) = cos^2(๐‘Ž) - sin^2(๐‘Ž) to simplify further: -2sin(๐œƒ)cos(2๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ = -2sin(๐œƒ)(cos^2(๐œƒ) - sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ

Step 5: Apply the trigonometric identity sin^2(๐‘Ž) = 1 - cos^2(๐‘Ž) to simplify further: -2sin(๐œƒ)(cos^2(๐œƒ) - sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ = -2sin(๐œƒ)(1 - cos^2(๐œƒ) - sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ

Step 6: Simplify the expression further: -2sin(๐œƒ)(1 - (1 - sin^2(๐œƒ)) - sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ = -2sin(๐œƒ)(1 - 1 + sin^2(๐œƒ) - sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ

Step 7: Simplify the expression further: -2sin(๐œƒ)(2sin^2(๐œƒ))/๐‘๐‘œ๐‘ ๐œƒ = -4sin^3(๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ

Step 8: Apply the trigonometric identity sin(๐‘Ž)/cos(๐‘Ž) = tan(๐‘Ž) to simplify further: -4sin^3(๐œƒ)/๐‘๐‘œ๐‘ ๐œƒ = -4sin^3(๐œƒ)/sin(๐œƒ)/cos(๐œƒ)

Step 9: Simplify the expression further: -4sin^2(๐œƒ)/cos(๐œƒ) = -4sin(๐œƒ)/cos(๐œƒ)

Step 10: Apply the trigonometric identity sin(๐‘Ž)/cos(๐‘Ž) = tan(๐‘Ž) to simplify further: -4sin(๐œƒ)/cos(๐œƒ) = -4tan(๐œƒ)

Therefore, the limit as ๐œƒ approaches 0 of [๐‘ ๐‘–๐‘›๐œƒโˆ’๐‘ก๐‘Ž๐‘›๐œƒ๐‘ ๐‘–๐‘›3 ๐œƒ] is equal to -4tan(๐œƒ).

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