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A TV station is going to air a movie marathon with 8 movies. It will consist of 2 science fiction movies and 6 horror movies. The horror movies will be aired later in the evening. So, all of the horror movies will be aired last (after both of the science fiction movies). In how many ways can the station air the movie marathon?

Question

A TV station is going to air a movie marathon with 8 movies. It will consist of 2 science fiction movies and 6 horror movies. The horror movies will be aired later in the evening. So, all of the horror movies will be aired last (after both of the science fiction movies). In how many ways can the station air the movie marathon?

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Solution

To solve this problem, we need to consider two separate arrangements: the arrangement of the science fiction movies and the arrangement of the horror movies.

  1. First, let's consider the science fiction movies. There are 2 science fiction movies, so they can be arranged in 2! (2 factorial) ways. The factorial function (denoted with a !) means that you multiply the number by every number below it. So, 2! = 2*1 = 2. Therefore, there are 2 ways to arrange the science fiction movies.

  2. Next, let's consider the horror movies. There are 6 horror movies, so they can be arranged in 6! (6 factorial) ways. So, 6! = 65432*1 = 720. Therefore, there are 720 ways to arrange the horror movies.

  3. However, we need to consider the overall arrangement of the movies. The science fiction movies will always be aired before the horror movies. Therefore, we don't need to multiply the number of arrangements of the science fiction movies and the horror movies. The total number of ways the station can air the movie marathon is 2 * 720 = 1440 ways.

This problem has been solved

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