6. Complete the following stoichiometry problems. Need help? Watch this video. a. Determine the mass of lithium hydroxide produced when 0.38 grams of Li3 N reacts with water according to the following unbalanced chemical equation: ___Li3 N (s) + ___H2 O (l) → ___NH3 + ___LiOH b.
Question
- Complete the following stoichiometry problems. Need help? Watch this video. a. Determine the mass of lithium hydroxide produced when 0.38 grams of Li3 N reacts with water according to the following unbalanced chemical equation: ___Li3 N (s) + ___H2 O (l) → ___NH3 + ___LiOH b.
Solution
First, we need to balance the chemical equation. The balanced equation is:
Li3N + 3H2O → NH3 + 3LiOH
Next, we need to find the molar mass of Li3N and LiOH. The molar mass of Li3N is approximately 34.83 g/mol and the molar mass of LiOH is approximately 23.95 g/mol.
Then, we need to convert the given mass of Li3N to moles using its molar mass:
0.38 g Li3N * (1 mol Li3N / 34.83 g Li3N) = 0.0109 mol Li3N
According to the balanced equation, one mole of Li3N produces three moles of LiOH. So, we can find the moles of LiOH produced:
0.0109 mol Li3N * (3 mol LiOH / 1 mol Li3N) = 0.0327 mol LiOH
Finally, we convert the moles of LiOH to grams using its molar mass:
0.0327 mol LiOH * (23.95 g LiOH / 1 mol LiOH) = 0.783 g LiOH
So, when 0.38 grams of Li3N reacts with water, approximately 0.783 grams of lithium hydroxide is produced.
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