Sushil got married 6 years ago. His age is 76 times of his age at the time of his marriage. Three years ago, his son was 3 years old. The ratio of his Son and Sushil at present is?Options6:11:71:6
Question
Sushil got married 6 years ago. His age is 76 times of his age at the time of his marriage. Three years ago, his son was 3 years old. The ratio of his Son and Sushil at present is?Options6:11:71:6
Solution
Let's break down the problem step by step:
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Sushil got married 6 years ago. His present age is 76 times his age at the time of his marriage. This means if his age at the time of marriage was x, then his present age is 76x.
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Since he got married 6 years ago, his age at the time of marriage was (76x - 6).
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According to the problem, his age at the time of marriage is equal to 1 (since his present age is 76 times this). So, we can set up the equation 76x - 6 = 1.
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Solving for x gives us x = 7/76 years. This means Sushil was 7/76 years old when he got married.
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His present age is 76 times this, which is 7 years.
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Three years ago, his son was 3 years old. This means his son is now 6 years old.
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The ratio of his son's age to Sushil's age is 6:7.
So, the answer is 6:7.
Similar Questions
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