Kamla got married 6 years ago. Today her age is 11/4 times her age at the time of marriage. Her son's age is (1/10) times of her age. Her son's age is ?Choices:- 2 3 4 5
Question
Kamla got married 6 years ago. Today her age is 11/4 times her age at the time of marriage. Her son's age is (1/10) times of her age. Her son's age is ?Choices:- 2 3 4 5
Solution
Let's solve this step by step:
Step 1: Let's assume Kamla's age at the time of her marriage was 'x' years.
Step 2: According to the problem, Kamla's current age is 11/4 times her age at the time of marriage. So, her current age is 11x/4 years.
Step 3: The problem also states that Kamla got married 6 years ago. So, her current age is also 'x + 6' years.
Step 4: Now, we can set up the equation 11x/4 = x + 6.
Step 5: To solve for 'x', we first multiply each side of the equation by 4 to get rid of the fraction: 11x = 4x + 24.
Step 6: Then, we subtract 4x from each side to isolate 'x': 11x - 4x = 24, which simplifies to 7x = 24.
Step 7: Finally, we divide each side by 7 to solve for 'x': x = 24/7, which simplifies to x = 3.43 (approximately).
Step 8: Now, we know that Kamla's age at the time of her marriage was approximately 3.43 years. But age is always a whole number, so we round it up to 4 years.
Step 9: The problem states that Kamla's son's age is 1/10 times her current age. So, her son's age is (11/4) * 4 * (1/10) = 11/10 = 1.1 years.
Step 10: Again, since age is always a whole number, we round 1.1 up to the nearest whole number, which is 2.
So, Kamla's son's age is 2 years.
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