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Instructions: Use the atomic weights for the elements in your Equation Booklet and the following figure to compute problem 1 seen below.--Given Values--- = Data for Problem 1Molecular Weight Data Table for = Polystyrene (PS)- = Molecular Wt(g/mol)|----xi--- |-- wi- = 8,000 - 16,000 -------|-- 0.03 --|--0.04- = 16,000 - 24,000 ------|-- 0.16 --|--0.12- = 24,000 - 32,000 ------|-- 0.25 --|--0.20- = 32,000 - 40,000 ------|-- 0.29 --|--0.28- = 40,000 - 48,000 ------|-- 0.19 --|--0.29- = 48,000 - 56,000------|-- 0.08 --|--0.13- = Data for Problem 2Required Tensile Strength (MPa) = 154Tensile Strength (MPa) for PE 1 = 77Tensile Strength (MPa) for PE 2 = 160Number-Average Molecular Weight (g/mol) for PE 1 = 17,886Number-Average Molecular Weight (g/mol) for PE 2 = 26,247Problem 1 Part A :For the polymer listed, given the mass range in (g/mol) and Ni (number fraction) and wi(weight fraction). Compute the number - average molecular weight for the polymer.        Your Answer =Problem 1 Part B:Calculate the weight - average molecular weight for the polymer        Your Answer =Problem 1 Part C:The degree of polymerization of for the polymer listed.        Your Answer =Problem 2 Part A:The tensile strength and number-average molecular weight for two polyethylene materials given above. Estimate the number-average molecular weight that is required to give a tensile strength required above. Using the data given find TS (infinity) in MPa        Your Answer =Problem 2 Part B:Using the data given in the problem, find A in Mpa-g/mol.        Your Answer =Problem 2 Part C:What is the number-average molecular weight that is required to give a tensile strength required above?        Your Answer =

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Instructions: Use the atomic weights for the elements in your Equation Booklet and the following figure to compute problem 1 seen below.--Given Values--- = Data for Problem 1Molecular Weight Data Table for = Polystyrene (PS)- = Molecular Wt(g/mol)|----xi--- |-- wi- = 8,000 - 16,000 -------|-- 0.03 --|--0.04- = 16,000 - 24,000 ------|-- 0.16 --|--0.12- = 24,000 - 32,000 ------|-- 0.25 --|--0.20- = 32,000 - 40,000 ------|-- 0.29 --|--0.28- = 40,000 - 48,000 ------|-- 0.19 --|--0.29- = 48,000 - 56,000------|-- 0.08 --|--0.13- = Data for Problem 2Required Tensile Strength (MPa) = 154Tensile Strength (MPa) for PE 1 = 77Tensile Strength (MPa) for PE 2 = 160Number-Average Molecular Weight (g/mol) for PE 1 = 17,886Number-Average Molecular Weight (g/mol) for PE 2 = 26,247Problem 1 Part A :For the polymer listed, given the mass range in (g/mol) and Ni (number fraction) and wi(weight fraction). Compute the number - average molecular weight for the polymer.        Your Answer =Problem 1 Part B:Calculate the weight - average molecular weight for the polymer        Your Answer =Problem 1 Part C:The degree of polymerization of for the polymer listed.        Your Answer =Problem 2 Part A:The tensile strength and number-average molecular weight for two polyethylene materials given above. Estimate the number-average molecular weight that is required to give a tensile strength required above. Using the data given find TS (infinity) in MPa        Your Answer =Problem 2 Part B:Using the data given in the problem, find A in Mpa-g/mol.        Your Answer =Problem 2 Part C:What is the number-average molecular weight that is required to give a tensile strength required above?        Your Answer =

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