What is the binding energy of a mole of nuclei with a mass defect of 0.00084 kg/mol?A.7.56 × 1016 J/molB.2.52 × 108 J/molC.7.56 × 1013 J/molD.2.52 × 105 J/molSUBMITarrow_backPREVIOUS

The binding energy of a mole of nuclei can be calculated using Einstein's mass-energy equivalence principle, which states that E=mc^2, where E is energy, m is mass, and c is the speed of light.

Given: Mass defect (Δm) = 0.00084 kg/mol Speed of light (c) = 3.00 x 10^8 m/s

We can substitute these values into the equation:

E = Δm * c^2 E = 0.00084 kg/mol * (3.00 x 10^8 m/s)^2 E = 0.00084 kg/mol * 9.00 x 10^16 m^2/s^2 E = 7.56 x 10^13 J/mol

However, this is the energy for one kilogram of nuclei. Since the question asks for the energy of one mole of nuclei, we need to multiply this value by Avogadro's number (6.022 x 10^23), which gives us the number of nuclei in one mole.

E = 7.56 x 10^13 J/mol * 6.022 x 10^23 E = 4.55 x 10^37 J/mol

This value is not listed in the answer choices, which suggests that there may be a mistake in the question or the answer choices. However, if we consider the mass defect to be in units of kg per nucleus (rather than per mole), then the calculated energy would be per nucleus and we would not multiply by Avogadro's number. In that case, the answer would be:

E = 7.56 x 10^13 J/nucleus

This value is closest to answer choice C, so that may be the intended answer. However, without clarification on the units of the mass defect, it's impossible to say for certain.