Find out equivalent mass of KMnO4 in acidic medium of molar mass is M :M/5M/3M/1M/4

To find the equivalent mass of KMnO4 in acidic medium, we need to consider the balanced redox reaction that occurs in the presence of acid. In this case, KMnO4 acts as an oxidizing agent and gets reduced to Mn2+ ions.

The balanced equation for the reaction is:

2MnO4- + 16H+ + 10e- -> 2Mn2+ + 8H2O

From the balanced equation, we can see that 2 moles of KMnO4 react with 5 moles of electrons (10 moles of electrons for 2 moles of KMnO4).

Now, let's calculate the equivalent mass of KMnO4.

Equivalent mass = Molar mass / moles of electrons

Given that the molar mass of KMnO4 is M, we can substitute the values into the equation:

Equivalent mass = M / 10

Therefore, the equivalent mass of KMnO4 in acidic medium is M/10.