A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time? (Hint: the equation for for uniform acceleration is v2 – u2 = 2as)
Question
A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time? (Hint: the equation for for uniform acceleration is v2 – u2 = 2as)
Solution
Sure, here's how to solve this problem:
Step 1: Identify the given values. Initial velocity (u) = 15 m/s Acceleration (a) = 3 m/s² Time (t) = 20 seconds
Step 2: Use the equation of motion to find the final velocity (v). v = u + at v = 15 m/s + (3 m/s² * 20 s) v = 15 m/s + 60 m/s v = 75 m/s
Step 3: Use the equation for uniform acceleration to find the distance (s). v² – u² = 2as 75² m²/s² - 15² m²/s² = 2 * 3 m/s² * s 5625 m²/s² - 225 m²/s² = 6 m/s² * s 5400 m²/s² = 6 m/s² * s s = 5400 m²/s² / 6 m/s² s = 900 meters
So, the train travels 900 meters in 20 seconds.
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