What velocity is an object moving at after 6.0s if it is moving at 45m/s initially, 36m/s after 2.0s and 27m/s after 4.0s?

To solve this problem, we first need to find the acceleration of the object. Acceleration is the rate of change of velocity with respect to time.

Step 1: Calculate the acceleration between the initial time and 2.0s. Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time (t) a = (36m/s - 45m/s) / 2.0s a = -9m/s^2 / 2.0s a = -4.5m/s^2

Step 2: Verify the acceleration between 2.0s and 4.0s to ensure it's constant. a = (27m/s - 36m/s) / 2.0s a = -9m/s^2 / 2.0s a = -4.5m/s^2

The acceleration is constant, so we can use it to find the velocity at 6.0s.

Step 3: Calculate the velocity at 6.0s. Final velocity = Initial velocity + (Acceleration * Time) v = 27m/s + (-4.5m/s^2 * 2.0s) v = 27m/s - 9m/s v = 18m/s

So, the object is moving at 18m/s after 6.0s.