What is the velocity of an object accelerating at −25.0m/s 2 after 6.0s when it is initially moving at 30.0m/s?
Question
What is the velocity of an object accelerating at −25.0m/s 2 after 6.0s when it is initially moving at 30.0m/s?
Solution
Sure, here's how you can calculate the velocity of the object:
Step 1: Understand the given values. The initial velocity (u) = 30.0 m/s The acceleration (a) = -25.0 m/s² The time (t) = 6.0 s
Step 2: Use the formula for velocity when acceleration and time are known. The formula is: v = u + at
Step 3: Substitute the given values into the formula. v = 30.0 m/s + (-25.0 m/s² * 6.0 s)
Step 4: Solve the equation. v = 30.0 m/s - 150.0 m/s v = -120.0 m/s
So, the velocity of the object after 6.0 seconds is -120.0 m/s. The negative sign indicates that the object is moving in the opposite direction to the initial direction.
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