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Two cyclists start travelling from cities X and Y moving towards each other with a uniform speed of 5 kmph each. At the same time, an athlete starts running from the city X. When both cyclists meet the athlete covers a distance of 4 kms. If the distance between X and Y is 40 kms, then find the speed of the athlete.  Ops:   A. 4 kmph    B. 1 kmph    C. 2 kmph    D. 3 kmph

Question

Two cyclists start travelling from cities X and Y moving towards each other with a uniform speed of 5 kmph each. At the same time, an athlete starts running from the city X. When both cyclists meet the athlete covers a distance of 4 kms. If the distance between X and Y is 40 kms, then find the speed of the athlete.  Ops:   A. 4 kmph    B. 1 kmph    C. 2 kmph    D. 3 kmph

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Solution

Step 1: Understand the problem

Two cyclists are moving towards each other from two different cities X and Y. They are moving at a uniform speed of 5 kmph each. At the same time, an athlete starts running from city X. When the cyclists meet, the athlete has covered a distance of 4 kms. The distance between the two cities is 40 kms. We need to find the speed of the athlete.

Step 2: Calculate the time taken for the cyclists to meet

The cyclists are moving towards each other, so their relative speed is the sum of their individual speeds, which is 5 kmph + 5 kmph = 10 kmph. The distance between the cities is 40 kms. So, the time taken for the cyclists to meet is the distance divided by the relative speed, which is 40 kms / 10 kmph = 4 hours.

Step 3: Calculate the speed of the athlete

The athlete has covered a distance of 4 kms in the time it takes for the cyclists to meet, which is 4 hours. So, the speed of the athlete is the distance covered divided by the time taken, which is 4 kms / 4 hours = 1 kmph.

So, the speed of the athlete is 1 kmph. The correct answer is B. 1 kmph.

This problem has been solved

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