Knowee
Questions
Features
Study Tools

250 g250 g solution of DD-glucose in water contains 10.8%10.8% of carbon by weight. The molality of the solution is nearest to (Given: Atomic Weights are H=1u; C=12 u; O=16 uH=1u; C=12 u; O=16 u)

Question

250 g250 g solution of DD-glucose in water contains 10.8%10.8% of carbon by weight. The molality of the solution is nearest to (Given: Atomic Weights are H=1u; C=12 u; O=16 uH=1u; C=12 u; O=16 u)

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the molality of the solution, we need to calculate the number of moles of glucose and the mass of water in the solution.

Step 1: Calculate the number of moles of carbon in the solution. Given that the solution contains 10.8% carbon by weight, we can calculate the mass of carbon in the solution using the formula: Mass of carbon = (10.8/100) * mass of solution

Step 2: Calculate the number of moles of glucose. Since glucose has the molecular formula C6H12O6, we know that there are 6 carbon atoms in one molecule of glucose. Therefore, the number of moles of glucose can be calculated using the formula: Number of moles of glucose = (Number of moles of carbon) / 6

Step 3: Calculate the mass of water in the solution. The mass of water can be calculated by subtracting the mass of glucose from the mass of the solution: Mass of water = mass of solution - mass of glucose

Step 4: Calculate the molality of the solution. Molality is defined as the number of moles of solute (glucose) per kilogram of solvent (water). Therefore, we can calculate the molality using the formula: Molality = (Number of moles of glucose) / (Mass of water in kg)

By following these steps, we can find the molality of the solution.

This problem has been solved

Similar Questions

If mass percentage of glucose in aqueous solution is 18% then molality of glucose in the solution will be3.5 m1.2 m0.5 m4.1 m

A solution of glucose has been prepared by dissolving 1.8 g of glucose in 200 g of water. The boiling point of the solution obtained will be (Kb for water = 0.52 K kg mol–1)

Calculate the mass of water and mass of glucose required to make 250 g of 40% solution of glucose.

What is the molarity of a glucose solution that contains 10.0 g of C6H12O6 (180.18 g/mol) dissolved in 100.0 mL of solution?Group of answer choices 1.80 M18.0 M0.00555 M0.555 M 0.0555 M

f the concentration of glucose (CcH20s) in blood is 0.9g/L, what will be themolarity of glucose in blood.a) 5M b) 50M c) 0.005M d) 0.5MIf the density of asolution is 3.12grb4, the mass of 1.5ml solution isa) 4.7g b)4680x10°g c) 4.680g d) 46.80gc)Assertion: The molality of the solution does not change with change intemperature.Reason: The molality if expressed in units of moles per 1000 gm of solvent.a) Both Aand Rare true and Ris correct explanation of A.b) Both Aand Rare true but Ris not the correct explanation ofA.QUESTIONSSECTIONAA is true but Ris false.d) Both Aand Rare false.At NTP what will be the no. of molecules of 6.022X1023 H2?a) 1g Aua) 22.4 Litres b) 11.2 Litres c) 5.6 Litres d) Noneb) 1g NaCalculate the number of molecules present in 0.5 moles of CO;?a) 3.011x1023 b) 6.022x1023 c) 1.056 X1023 d) nonec) 1g LiWhich one of the foilowing will have largest number of atoms.d) 1g Cl2Which of thefollowing solutions have same concentration.a) 20g Na OH in 200 mL of solutionb) 0.5mol of KCl in 200mL of solution.c) 40g of NaOH in 100mL of solution.MAXIMUM MARKS:70CH/2022-23/SENIOR SECONDARYChrysas1MARKS1111111

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.