What is the molarity of a glucose solution that contains 10.0 g of C6H12O6 (180.18 g/mol) dissolved in 100.0 mL of solution?Group of answer choices 1.80 M18.0 M0.00555 M0.555 M 0.0555 M
Question
What is the molarity of a glucose solution that contains 10.0 g of C6H12O6 (180.18 g/mol) dissolved in 100.0 mL of solution?Group of answer choices 1.80 M18.0 M0.00555 M0.555 M 0.0555 M
Solution
First, we need to convert the mass of glucose into moles. We do this by dividing the mass of glucose by its molar mass.
Moles of glucose = 10.0 g / 180.18 g/mol = 0.0555 mol
Next, we need to convert the volume of the solution from milliliters to liters, since molarity is defined as moles of solute per liter of solution.
Volume of solution = 100.0 mL = 0.100 L
Finally, we calculate the molarity by dividing the moles of glucose by the volume of the solution in liters.
Molarity = 0.0555 mol / 0.100 L = 0.555 M
So, the molarity of the glucose solution is 0.555 M.
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