A galvanometer having a coil resistance of 30Ω shows full scale deflection when a current of 2A passes through it. It can be converted into an ammeter to read currents upto 10A by :-by putting in series a resistance of 240Ωby putting in parallel a resistance of 240Ωby putting in series a resistance of 7.5Ωby putting in parallel a resistance of 7.5Ω
Question
A galvanometer having a coil resistance of 30Ω shows full scale deflection when a current of 2A passes through it. It can be converted into an ammeter to read currents upto 10A by :-by putting in series a resistance of 240Ωby putting in parallel a resistance of 240Ωby putting in series a resistance of 7.5Ωby putting in parallel a resistance of 7.5Ω
Solution
To convert a galvanometer into an ammeter, we need to connect a shunt resistance in parallel with it. The shunt resistance (Rs) can be calculated using the formula:
Rs = (Rg * Ig) / (Imax - Ig)
where: Rg = resistance of the galvanometer = 30Ω Ig = current for full scale deflection in the galvanometer = 2A Imax = maximum current to be measured = 10A
Substituting the given values into the formula, we get:
Rs = (30 * 2) / (10 - 2) = 60 / 8 = 7.5Ω
Therefore, to convert the galvanometer into an ammeter that can read currents up to 10A, we need to put a resistance of 7.5Ω in parallel with the galvanometer.
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