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In half deflection method, the resistance of resistance box in series with the galvanometer is 10,000 Ω. When the galvanometer is shunted with 10 Ω resistance, its reading drops to half the initial value. The resistance of galvanometer is :-

Question

In half deflection method, the resistance of resistance box in series with the galvanometer is 10,000 Ω. When the galvanometer is shunted with 10 Ω resistance, its reading drops to half the initial value. The resistance of galvanometer is :-

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Solution

The half deflection method is a technique used to measure the resistance of a galvanometer. Here's how you can calculate the resistance of the galvanometer in this case:

Step 1: Understand the concept of shunt resistance. When a resistance (in this case, 10 Ω) is connected in parallel with the galvanometer, it is called a shunt resistance. The purpose of this is to allow most of the current to bypass the galvanometer so that it doesn't get damaged by high current.

Step 2: Use the formula for calculating resistance in parallel circuits. When two resistances R1 and R2 are connected in parallel, their total resistance R is given by the formula 1/R = 1/R1 + 1/R2.

Step 3: In this case, the resistance of the resistance box (R1) is 10,000 Ω and the shunt resistance (R2) is 10 Ω. The total resistance when the galvanometer reading drops to half is also 10,000 Ω (since the resistance box is in series with the galvanometer-shunt combination).

Step 4: Substitute these values into the formula: 1/10,000 = 1/10,000 + 1/R2.

Step 5: Solve the equation for R2. This will give you the resistance of the galvanometer.

After solving, you will find that the resistance of the galvanometer is approximately 20 Ω.

This problem has been solved

Similar Questions

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