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Calculate the area of the triangle shown. Round your final answer to the nearest whole number.View Image DescriptionA triangle labeled ABC on a coordinate plane.Side AC has length of 9.24 units.Side BC and AB each have a length of 14 units.The height is indicated by a dashed line extending through the interior of the triangle from angle B to side AC. It is 13.22 units.110 units squared65 units squared125 inches squared61 units squared

Question

Calculate the area of the triangle shown. Round your final answer to the nearest whole number.View Image DescriptionA triangle labeled ABC on a coordinate plane.Side AC has length of 9.24 units.Side BC and AB each have a length of 14 units.The height is indicated by a dashed line extending through the interior of the triangle from angle B to side AC. It is 13.22 units.110 units squared65 units squared125 inches squared61 units squared

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Solution

To calculate the area of a triangle, you can use the formula:

Area=12×base×height \text{Area} = \frac{1}{2} \times \text{base} \times \text{height}

Given:

  • The base AC AC has a length of 9.24 units.
  • The height from point B to side AC is 13.22 units.

Let's plug these values into the formula:

Area=12×9.24×13.22 \text{Area} = \frac{1}{2} \times 9.24 \times 13.22

First, multiply the base by the height:

9.24×13.22=122.0808 9.24 \times 13.22 = 122.0808

Next, multiply by 12\frac{1}{2}:

12×122.0808=61.0404 \frac{1}{2} \times 122.0808 = 61.0404

Finally, round the result to the nearest whole number:

61.040461 61.0404 \approx 61

So, the area of the triangle is approximately 61 square units.

The correct answer is:

61 units squared \boxed{61 \text{ units squared}}

This problem has been solved

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