The y-intercept of a function is the point where the line crosses the y-axis. This happens when x = 0.

The given function is y = -14(x+2)^2 + 1.

To find the y-intercept, we substitute x = 0 into the function:

y = -14(0+2)^2 + 1
y = -14(2)^2 + 1
y = -14*4 + 1
y = -56 + 1
y = -55

So, the y-intercept of the function is -55.

Question

The y-intercept of a function is the point where the line crosses the y-axis. This happens when x = 0.

The given function is y = -14(x+2)^2 + 1.

To find the y-intercept, we substitute x = 0 into the function:

y = -14(0+2)^2 + 1
y = -14(2)^2 + 1
y = -14*4 + 1
y = -56 + 1
y = -55

So, the y-intercept of the function is -55.

Knowee AI · Accepted Answer

The y-intercept of a function is the point where the line crosses the y-axis. This happens when x = 0.

The given function is y = -14(x+2)^2 + 1.

To find the y-intercept, we substitute x = 0 into the function:

y = -14(0+2)^2 + 1
y = -14(2)^2 + 1
y = -14*4 + 1
y = -56 + 1
y = -55

So, the y-intercept of the function is -55.

Identify the following y-intercept from the function below. Type your answer as just the numerical y-value.y=−14(x+2)2+1