Calculate the energy needed to increase the temperature by 38 °C for 0.2 kg of iron.The specific heat capacity of iron is 449 J/kg°C.You must include units in your answer.
Question
Calculate the energy needed to increase the temperature by 38 °C for 0.2 kg of iron.The specific heat capacity of iron is 449 J/kg°C.You must include units in your answer.
Solution
To calculate the energy needed, we can use the formula for heat transfer:
Q = mcΔT
where:
- Q is the heat energy (in Joules, J)
- m is the mass (in kilograms, kg)
- c is the specific heat capacity (in Joules per kilogram per degree Celsius, J/kg°C)
- ΔT is the change in temperature (in degrees Celsius, °C)
Given:
- m = 0.2 kg
- c = 449 J/kg°C
- ΔT = 38 °C
Substituting these values into the formula, we get:
Q = 0.2 kg * 449 J/kg°C * 38 °C
Q = 3414.4 J
So, the energy needed to increase the temperature by 38 °C for 0.2 kg of iron is 3414.4 Joules.
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