4. Represent the following as a single precision floating point (IEEE 754) number:a) 85.125b) -4.75
Question
- Represent the following as a single precision floating point (IEEE 754) number:a) 85.125b) -4.75
Solution
Sure, let's break it down step by step:
a) 85.125
Step 1: Convert the integer part to binary 85 in decimal is 1010101 in binary.
Step 2: Convert the fractional part to binary 0.125 in decimal is 0.001 in binary.
So, 85.125 in binary is 1010101.001
Step 3: Normalize the binary number This gives us 1.010101001 x 2^6
Step 4: Determine the sign, exponent, and mantissa The sign is 0 (since the number is positive), the exponent is 6, and the mantissa is 010101001.
Step 5: Adjust the exponent by adding 127 (for single precision) and convert to binary 6 + 127 = 133, which is 10000101 in binary.
Step 6: Assemble the IEEE 754 representation This gives us 0 10000101 01010100100000000000000
b) -4.75
Step 1: Convert the integer part to binary 4 in decimal is 100 in binary.
Step 2: Convert the fractional part to binary 0.75 in decimal is 0.11 in binary.
So, -4.75 in binary is -100.11
Step 3: Normalize the binary number This gives us -1.0011 x 2^2
Step 4: Determine the sign, exponent, and mantissa The sign is 1 (since the number is negative), the exponent is 2, and the mantissa is 0011.
Step 5: Adjust the exponent by adding 127 (for single precision) and convert to binary 2 + 127 = 129, which is 10000001 in binary.
Step 6: Assemble the IEEE 754 representation This gives us 1 10000001 00110000000000000000000
Similar Questions
Represent the following as a single precision floating point (IEEE 754) number:a) 85.125b) -4.75
In the IEEE 754 standard, what components make up the floating-point representation of a number?
Construct -33.75 to IEEE 754 Single precision floating point number. Explainhow zero is represented in this format.
Explain IEEE 754 Floating point representations.
Single-precision IEEE-754 floating-point numbers are represented as follows:(-1)S * (1.M)*2(E - Bias)(Bias = 127)For the binary value 11000010 01111001 00000000 00000000 in single-precision IEEE-754floating point form, convert it to its decimal representation.S = 1 so negative numberExponent = 10000100 = 128 + 4 = 132132 – 127 (bias) = 5Mantissa = 1.1111001Shift binary point 5 spaces = 111110.01Translate LHS = 2+4+8+16+32 (or 64-2) = 62Translate RHS = 0.25S+LHS+RHS = -62.25(6 marks)S Expon
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