Construct -33.75 to IEEE 754 Single precision floating point number. Explainhow zero is represented in this format.
Question
Construct -33.75 to IEEE 754 Single precision floating point number. Explainhow zero is represented in this format.
Solution 1
Step 1: Identify the sign The number is negative, so the sign bit is 1.
Step 2: Convert the absolute value of the number to binary The absolute value of -33.75 is 33.75. The integer part 33 in binary is 100001. The fractional part 0.75 in binary is 0.11. So, 33.75 in binary is 100001.11.
Step 3: Normalize the binary number Move the binary point 5 places to the left to make the number between 1 and 2. The normalized number is 1.0000111. The exponent is 5.
Step 4: Add the bias to the exponent The bias for single precision IEEE 754 is 127. So, the biased exponent is 5 + 127 = 132. The binary representation of 132 is 10000100.
Step 5: Write out the mantissa The mantissa is the part after the binary point in the normalized number. So, the mantissa is 0000111000...0 (23 bits in total).
Step 6: Put it all together The IEEE 754 representation is therefore: Sign bit: 1 Exponent: 10000100 Mantissa: 0000111000...0 So, -33.75 in IEEE 754 single precision floating point number is 1 10000100 0000111000...0.
Zero in IEEE 754 format is represented as 0 00000000 0000000000...0 where the first 0 is the sign bit, the next 8 zeros are the exponent, and the last 23 zeros are the mantissa. This represents +0. There is also a -0, which has a sign bit of 1.
Solution 2
To convert -33.75 into IEEE 754 Single Precision Floating Point representation, follow these steps:
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Sign Bit: Since the number is negative, the sign bit is 1.
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Convert to Binary: Convert the absolute value of the number to binary. The integer part, 33, converts to 100001. The fractional part, .75, converts to .11. So, 33.75 in binary is 100001.11.
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Normalize: Move the binary point to the left of the most significant 1 and count the number of moves. The normalized form is 1.0000111 x 2^5.
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Exponent: Add 127 to the number of moves (5 in this case) to get the exponent in excess-127 form. 5 + 127 = 132, which is 10000100 in binary.
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Mantissa: Take the fraction part of the normalized form (0000111) and pad it with zeros on the right to make it 23 bits long. So, the mantissa is 00001110000000000000000.
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Combine: Combine the sign bit, exponent, and mantissa to get the final IEEE 754 representation: 1 10000100 00001110000000000000000.
As for representing zero in this format, it's quite simple. The sign can be either 0 (for +0) or 1 (for -0), the exponent is all zeros, and the mantissa is also all zeros. So, +0 is represented as 0 00000000 00000000000000000000000 and -0 is represented as 1 00000000 00000000000000000000000.
Similar Questions
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