First, we need to convert the solubility of compound X from g/mL to mg/mL for consistency with the mass of X given (130 mg).

1 g = 1000 mg

So, 0.111 g/mL = 111 mg/mL

This means that 1 mL of water can dissolve 111 mg of compound X at 20°C.

Next, we calculate the volume of water needed to dissolve 130 mg of compound X. We can use the formula:

Volume (mL) = Mass (mg) / Solubility (mg/mL)

Substituting the given values:

Volume (mL) = 130 mg / 111 mg/mL = 1.17117117117 mL

Rounding to the correct number of significant figures (three, based on the given values), the volume is approximately 1.17 mL. So, you would need about 1.17 mL of a saturated solution of compound X at 20°C to contain 130 mg of X.

Question

First, we need to convert the solubility of compound X from g/mL to mg/mL for consistency with the mass of X given (130 mg).

1 g = 1000 mg

So, 0.111 g/mL = 111 mg/mL

This means that 1 mL of water can dissolve 111 mg of compound X at 20°C.

Next, we calculate the volume of water needed to dissolve 130 mg of compound X. We can use the formula:

Volume (mL) = Mass (mg) / Solubility (mg/mL)

Substituting the given values:

Volume (mL) = 130 mg / 111 mg/mL = 1.17117117117 mL

Rounding to the correct number of significant figures (three, based on the given values), the volume is approximately 1.17 mL. So, you would need about 1.17 mL of a saturated solution of compound X at 20°C to contain 130 mg of X.

Knowee AI · Accepted Answer

First, we need to convert the solubility of compound X from g/mL to mg/mL for consistency with the mass of X given (130 mg).

1 g = 1000 mg

So, 0.111 g/mL = 111 mg/mL

This means that 1 mL of water can dissolve 111 mg of compound X at 20°C.

Next, we calculate the volume of water needed to dissolve 130 mg of compound X. We can use the formula:

Volume (mL) = Mass (mg) / Solubility (mg/mL)

Substituting the given values:

Volume (mL) = 130 mg / 111 mg/mL = 1.17117117117 mL

Rounding to the correct number of significant figures (three, based on the given values), the volume is approximately 1.17 mL. So, you would need about 1.17 mL of a saturated solution of compound X at 20°C to contain 130 mg of X.

The solubility in water of ionic compound X is measured and found to be 0.111gmL at 20.°C. Calculate the volume of a saturated solution of X in water that would contain 130.mg of X at this temperature.Be sure your answer has the correct unit symbol and number of significant digits.

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