The carrier concentration in a material of conductivity 0.018/ohm m is 1019 electrons/m3. A voltage of 0.16 volts is applied across the 0.29 mm thick material. Determine the driftvelocity of the carriers. Take standard values of mass of electron and electronic charge.
Question
The carrier concentration in a material of conductivity 0.018/ohm m is 1019 electrons/m3. A voltage of 0.16 volts is applied across the 0.29 mm thick material. Determine the driftvelocity of the carriers. Take standard values of mass of electron and electronic charge.
Solution
To find the drift velocity, we first need to find the current density (J) using Ohm's law. Ohm's law states that J = σE, where σ is the conductivity and E is the electric field.
Step 1: Convert the thickness of the material from mm to m. 0.29 mm = 0.29 x 10^-3 m = 2.9 x 10^-4 m
Step 2: Calculate the electric field (E) using the formula E = V/d, where V is the voltage and d is the thickness of the material. E = 0.16 V / 2.9 x 10^-4 m = 5.52 x 10^5 V/m
Step 3: Calculate the current density (J) using Ohm's law. J = σE = 0.018/ohm m * 5.52 x 10^5 V/m = 9936 A/m^2
Step 4: Calculate the drift velocity (v) using the formula v = J / (nq), where n is the carrier concentration and q is the charge of an electron. The charge of an electron (q) is 1.6 x 10^-19 C.
v = 9936 A/m^2 / (10^19 electrons/m^3 * 1.6 x 10^-19 C/electron) = 0.062 m/s
So, the drift velocity of the carriers is 0.062 m/s.
Similar Questions
The resistivity of a pure semiconductor is 0.5 Ωm. If the electron and hole mobility be 0.39 m2/V-s and 0.21 m2/V-s respectively then calculate the intrinsic carrier concentration.2.08 × 1019/m34.32 × 1019/m31020/m3None of these
The number density of conduction electrons in a particular metal is 1029 m-3. A current of 4 A flows through a wire of this material, which has a length of 1m and cross-sectional area of 2(mm)2. The voltage across the wire is 2.70x10-3 V. What is the average speed (drift speed) of the electrons in units of ms-1 to 3 significant figures using scientific notation (e.g. x.xxExx)?
An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 5.50 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire. The equation for the drift velocity includes the number of charge carriers per volume, which in this case is equal to the number of atoms per volume. How do you calculate that if you know the density and the atomic weight of aluminum? mm
Consider a conductor of length 0.5 m. A potential difference of 20V is applied across this conductor. If the drift velocity of electrons is given as 5.0 × 10-4ms-1, then determine the mobility of the electrons.
conductor of copper, the density of free electons is 5×10^23 electrons per unit volume, carrying current of intenisty 1.6A if the cross-sectional area of a conductor is 4mm^2 so the drift velocity of electrons is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.