The resistivity of a pure semiconductor is 0.5 Ωm. If the electron and hole mobility be 0.39 m2/V-s and 0.21 m2/V-s respectively then calculate the intrinsic carrier concentration.2.08 × 1019/m34.32 × 1019/m31020/m3None of these
Question
The resistivity of a pure semiconductor is 0.5 Ωm. If the electron and hole mobility be 0.39 m2/V-s and 0.21 m2/V-s respectively then calculate the intrinsic carrier concentration.2.08 × 1019/m34.32 × 1019/m31020/m3None of these
Solution
The intrinsic carrier concentration (ni) can be calculated using the formula:
ni = 1 / (ρ * e * (μe + μh))
where: ρ is the resistivity (0.5 Ωm), e is the charge of an electron (1.6 x 10^-19 C), μe is the electron mobility (0.39 m^2/Vs), and μh is the hole mobility (0.21 m^2/Vs).
Substituting the given values into the formula, we get:
ni = 1 / (0.5 * 1.6 x 10^-19 * (0.39 + 0.21)) ni = 1 / (0.8 x 10^-19 * 0.6) ni = 1 / (0.48 x 10^-19) ni = 2.08 x 10^19 / m^3
So, the intrinsic carrier concentration is 2.08 x 10^19 / m^3.
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