If 3147m9744 is a nine-digit number divisible by both 8 and 9, then find m
Question
If 3147m9744 is a nine-digit number divisible by both 8 and 9, then find m
Solution
To find the value of 'm', we need to consider the rules of divisibility for 8 and 9.
- A number is divisible by 8 if the last three digits of the number form a number that is divisible by 8.
- A number is divisible by 9 if the sum of its digits is divisible by 9.
Let's apply these rules to the given number 3147m9744.
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For the number to be divisible by 8, 'm74' should be divisible by 8. The numbers that can be formed by replacing 'm' with digits from 0 to 9 and are divisible by 8 are 074, 174, 274, 374, 474, 574, 674, 774, 874, and 974. So, the possible values for 'm' considering divisibility by 8 are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
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For the number to be divisible by 9, the sum of its digits should be divisible by 9. The sum of the known digits is 3+1+4+7+9+7+4+4 = 39. If we add 'm' to this sum, the result should be divisible by 9. The only possible values for 'm' that make the sum divisible by 9 are 0 and 9.
Considering both conditions, the only common value for 'm' is 0. So, 'm' should be 0 for the number 3147m9744 to be divisible by both 8 and 9.
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