Find X, if the 6 digit number 56X412 is divisible by 9 ?0193

To find the value of X, we need to know that a number is divisible by 9 if the sum of its digits is divisible by 9.

Let's add the digits of the number 56X412:

5 + 6 + X + 4 + 1 + 2 = 18 + X

For 18 + X to be divisible by 9, X must be a number that, when added to 18, results in a multiple of 9. The possible values for X are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.

If X = 0, 18 + X = 18, which is a multiple of 9. If X = 1, 18 + X = 19, which is not a multiple of 9. If X = 2, 18 + X = 20, which is not a multiple of 9. If X = 3, 18 + X = 21, which is not a multiple of 9. If X = 4, 18 + X = 22, which is not a multiple of 9. If X = 5, 18 + X = 23, which is not a multiple of 9. If X = 6, 18 + X = 24, which is not a multiple of 9. If X = 7, 18 + X = 25, which is not a multiple of 9. If X = 8, 18 + X = 26, which is not a multiple of 9. If X = 9, 18 + X = 27, which is a multiple of 9.

So, the possible values for X are 0 and 9.